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antonblanchard.microwatt/countzero.vhdl
Paul Mackerras e527e3a9b7 countzero: Reorganize to have fewer levels of logic and fewer LUTs
By using 4:1 multiplexers rather than 2:1, this cuts the number of
levels of multiplexing from 4 to 2 and also reduces the total number
of slice LUTs required.  Because we are now handling 4 bits at each
level, including the bottom level, the logic to do the priority
encoding can be factored out into a function that is used at each
level.

This rearranges the logic so that the encoding and selection of bits
is done whether or not the input operand is zero, and the if statement
testing whether the input is zero only affects what is assigned to
result.  With this we don't get the inferred latches and we can go
back to using signals rather than variables.

Also add some comments about what is being done.

Signed-off-by: Paul Mackerras <paulus@ozlabs.org>
2019-10-14 08:43:38 +11:00

115 lines
3.0 KiB
VHDL

library ieee;
use ieee.std_logic_1164.all;
use ieee.numeric_std.all;
library work;
entity zero_counter is
port (
rs : in std_ulogic_vector(63 downto 0);
count_right : in std_ulogic;
is_32bit : in std_ulogic;
result : out std_ulogic_vector(63 downto 0)
);
end entity zero_counter;
architecture behaviour of zero_counter is
signal y, z : std_ulogic_vector(3 downto 0);
signal v16 : std_ulogic_vector(15 downto 0);
signal v4 : std_ulogic_vector(3 downto 0);
signal sel : std_ulogic_vector(5 downto 0);
-- Return the index of the leftmost or rightmost 1 in a set of 4 bits.
-- Assumes v is not "0000"; if it is, return (right ? "11" : "00").
function encoder(v: std_ulogic_vector(3 downto 0); right: std_ulogic) return std_ulogic_vector is
begin
if right = '0' then
if v(3) = '1' then
return "11";
elsif v(2) = '1' then
return "10";
elsif v(1) = '1' then
return "01";
else
return "00";
end if;
else
if v(0) = '1' then
return "00";
elsif v(1) = '1' then
return "01";
elsif v(2) = '1' then
return "10";
else
return "11";
end if;
end if;
end;
begin
zerocounter0: process(all)
begin
-- Test 4 groups of 16 bits each.
-- The top 2 groups are considered to be zero in 32-bit mode.
z(0) <= or (rs(15 downto 0));
z(1) <= or (rs(31 downto 16));
z(2) <= or (rs(47 downto 32));
z(3) <= or (rs(63 downto 48));
if is_32bit = '0' then
sel(5 downto 4) <= encoder(z, count_right);
else
sel(5) <= '0';
if count_right = '0' then
sel(4) <= z(1);
else
sel(4) <= not z(0);
end if;
end if;
-- Select the leftmost/rightmost non-zero group of 16 bits
case sel(5 downto 4) is
when "00" =>
v16 <= rs(15 downto 0);
when "01" =>
v16 <= rs(31 downto 16);
when "10" =>
v16 <= rs(47 downto 32);
when others =>
v16 <= rs(63 downto 48);
end case;
-- Test 4 groups of 4 bits
y(0) <= or (v16(3 downto 0));
y(1) <= or (v16(7 downto 4));
y(2) <= or (v16(11 downto 8));
y(3) <= or (v16(15 downto 12));
sel(3 downto 2) <= encoder(y, count_right);
-- Select the leftmost/rightmost non-zero group of 4 bits
case sel(3 downto 2) is
when "00" =>
v4 <= v16(3 downto 0);
when "01" =>
v4 <= v16(7 downto 4);
when "10" =>
v4 <= v16(11 downto 8);
when others =>
v4 <= v16(15 downto 12);
end case;
sel(1 downto 0) <= encoder(v4, count_right);
-- sel is now the index of the leftmost/rightmost 1 bit in rs
if v4 = "0000" then
-- operand is zero, return 32 for 32-bit, else 64
result <= x"00000000000000" & '0' & not is_32bit & is_32bit & "00000";
elsif count_right = '0' then
-- return (63 - sel), trimmed to 5 bits in 32-bit mode
result <= x"00000000000000" & "00" & (not sel(5) and not is_32bit) & not sel(4 downto 0);
else
result <= x"00000000000000" & "00" & sel;
end if;
end process;
end behaviour;